Calculate the osmotic pressure of 5% solution of urea at 273 kelvin temperature
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osmotic presuure=i∗C∗R∗T=i∗C∗R∗T
where, C=concentration of solute(in terms of Molarity)
R= Gas constant =0.082L(atm)(mol)−1K−1=0.082L(atm)(mol)−1K−1
T=temperature (in Kelvin)
i=Van’t-Hoff factor(=1 for non-electrolyte)
5%5% urea solution means 5g5g urea is present in 100ml of solution.
mole of urea=weight
given/Molecular weight of urea
=5g60gmol−1=112=5g60gmol−1=112
Hence Concentration of urea
(in terms of Molarity)
= (moles of urea(n) /volume of solution ) ×1000×1000
={(112)/100}∗1000={(112)/100}∗1000
=1012=1012
Hence Osmotic pressure =1×(10/20)×0.082×300=1×(10/20)×0.082×300 atm
where, C=concentration of solute(in terms of Molarity)
R= Gas constant =0.082L(atm)(mol)−1K−1=0.082L(atm)(mol)−1K−1
T=temperature (in Kelvin)
i=Van’t-Hoff factor(=1 for non-electrolyte)
5%5% urea solution means 5g5g urea is present in 100ml of solution.
mole of urea=weight
given/Molecular weight of urea
=5g60gmol−1=112=5g60gmol−1=112
Hence Concentration of urea
(in terms of Molarity)
= (moles of urea(n) /volume of solution ) ×1000×1000
={(112)/100}∗1000={(112)/100}∗1000
=1012=1012
Hence Osmotic pressure =1×(10/20)×0.082×300=1×(10/20)×0.082×300 atm
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