Question

calculate the Osmotic pressure of a 5% solution of glucose at 18 degree centigrade​

Answer 1

Answer:

The osmotic pressure of the 5% glucose solution is 6.97 atm.

Explanation:

5% of glucose solution

5 g of glucose in 95 grams of water.

Density of water = 1000 g/L

Volume of water =$\frac{Mass}{Density}=\frac{95 g}{1000 g/L}=0.095L$

Concentration of glucose solution:

$C=\frac{5 g}{180.15 g/mol\times 0.095 L}=0.2921 mol/L$

Temperature of the solution = 18°C = 291 K

Osmotic pressure of the solution:

$\pi=CRT=0.2921 mol/L\times 0.0820 atm L/mol K\times 291 K=6.97 atm$

The osmotic pressure of the 5% glucose solution is 6.97 atm.