calculate the osmotic pressure of a solution obtained by mixing one litre of 7.5 % solution of substance A (mol. weight= 75) and two litres of 5% solution of substance B (mol. weight =60) at 453K.
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Answer:
A =7.5%=75gL
−1
B=5%=50gL
−1
=100g(2L)
−1
Total volume =3 L=3000 mL
Mw
A
=
Mw
2
×Volumeofsolution
W
2
×1000
=
75×3000
75×1000
=0.33
Mw
B
=
60×3000
100×1000
=0.555
π=(Mw
A
+Mw
B
)RT
=(0.33+0.555)×0.082×453
=0.888×0.082×453=33.05atm
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