Calculate the osmotic pressure of a solution obtained by mixing 100ml of 1.5% solution of urea and 100 ml of 3.42% of cane sugar at 20
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Urea and cane sugar are very dissolvable in water. But we assume these molecules cannot pass through a semipermeable membrane. Only water can pass through.
Π = Osmotic pressure = C_solute * R T
R = 8.314 J/°K
C_solutes = Molar concentration of solutes
T = absolute temperature = 293 °K given
We assume that the volume of Urea and Cane sugar in the solutions are negligible as the concentrations are low.
Molar concentration: in 200 ml we have
Solutes = 3.4 / 60 moles of Urea + 1.6 /342 moles of cane sugar
= 0.061 moles
= 0.061 * 1000ml /200 ml = 0.306 M
Since Cane sugar and Urea are not Ionic, we do not multiply the concentration by any factor.
Osmotic pressure = Π = 0.306 * 8.314 * 293
= 745 Pa
Π = Osmotic pressure = C_solute * R T
R = 8.314 J/°K
C_solutes = Molar concentration of solutes
T = absolute temperature = 293 °K given
We assume that the volume of Urea and Cane sugar in the solutions are negligible as the concentrations are low.
Molar concentration: in 200 ml we have
Solutes = 3.4 / 60 moles of Urea + 1.6 /342 moles of cane sugar
= 0.061 moles
= 0.061 * 1000ml /200 ml = 0.306 M
Since Cane sugar and Urea are not Ionic, we do not multiply the concentration by any factor.
Osmotic pressure = Π = 0.306 * 8.314 * 293
= 745 Pa
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