Calculate the oxidation number of. 1, N in NO3. 2, P in H4P2O7
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Answer:
1:- +6
2:- +5
Explanation:
NO3 -
O = -2
O3 = -6
H4P2O7
H = +1
P = +5
O = -2
1*4 + 5 *2 + 7*(-2) = 0
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