Question

Calculate the oxidation number of C in CH2 Cl2

Answer 1

1 carbon (oxidation no. = x) 
2 hydrogens (oxidation no. = +1) 
2 chlorines (oxidation no. = -1) 

therefore, 

0 = x + 2(+1) + 2(-1) 
0 = x + 2 + -2 
0 = x + 0 
x = 0.

Answer 2

Answer:

It was 0

Explanation:

As hydrogen o.s is +1 but there are 2 hydrogen so +2 o.s

And cholrine is an electronegative element but it shows variable o.s -1,+3,+5,+7.. so they did not asked whether the chlorine is in + or - state s we should take -1 o.s

So final answer is

x + (+1)2 + (-1) 2

x +2-2=0

=O