Calculate the oxidation number of C in CH2 Cl2
Answers
Answered by
48
1 carbon (oxidation no. = x)
2 hydrogens (oxidation no. = +1)
2 chlorines (oxidation no. = -1)
therefore,
0 = x + 2(+1) + 2(-1)
0 = x + 2 + -2
0 = x + 0
x = 0.
2 hydrogens (oxidation no. = +1)
2 chlorines (oxidation no. = -1)
therefore,
0 = x + 2(+1) + 2(-1)
0 = x + 2 + -2
0 = x + 0
x = 0.
Answered by
15
Answer:
It was 0
Explanation:
As hydrogen o.s is +1 but there are 2 hydrogen so +2 o.s
And cholrine is an electronegative element but it shows variable o.s -1,+3,+5,+7.. so they did not asked whether the chlorine is in + or - state s we should take -1 o.s
So final answer is
x + (+1)2 + (-1) 2
x +2-2=0
=O
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