Chemistry, asked by tatineninivas, 5 months ago

calculate the oxidation number of co in ni(co)4​

Answers

Answered by BaapJi001
10

Answer:

The oxidation number of Ni in Ni(CO)4 is + 2 .

hope this helps you mate

always keep smiling.

take care!

Answered by Gushu16GHUFIA21Ashu
10

hi dude

here's ur answer

Let x be the oxidation number of Ni in Ni(CO)

Let x be the oxidation number of Ni in Ni(CO) 4

Let x be the oxidation number of Ni in Ni(CO) 4

Let x be the oxidation number of Ni in Ni(CO) 4 .

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overall

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements in

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0Hence, x=0.

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0Hence, x=0.Thus, the oxidation number of Ni in Ni(CO)

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0Hence, x=0.Thus, the oxidation number of Ni in Ni(CO) 4

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0Hence, x=0.Thus, the oxidation number of Ni in Ni(CO) 4

Let x be the oxidation number of Ni in Ni(CO) 4 .Since the overallcharge on the complex is 0, the sum of oxidation states of all elements init should be equal to 0.Therefore, x+4(0)=0Hence, x=0.Thus, the oxidation number of Ni in Ni(CO) 4 is 0.

HOPE IT HELPS U ✌️

Similar questions