Calculate the oxidation number of Cr in Cr2O7^-2.
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If oxidation number of Cr is x then
2x + 7(-2) = -2
2x = 12
x = +6
Oxidation number of Cr in Cr₂O₇²⁻ is +6
2x + 7(-2) = -2
2x = 12
x = +6
Oxidation number of Cr in Cr₂O₇²⁻ is +6
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