Question

Calculate the oxidation number of N in Pb(NO3)2.

Answer 1

hii. dear ..it will x-6= -2 then x= +4. hence oxidation num will be +4

Answer 2

The oxidation number of N in $Pb(NO_3)_2$ is +5

Explanation:

Rules for Oxidation Numbers :

1. The oxidation number of a free element is always zero.
2. The oxidation number of a monatomic ion equals the charge of the ion.
3. The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.
4. The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.
5. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is $Pb(NO_3)_2$

Let the oxidation state of N be, 'x'

$+2(1)+x(2)+-2(6)=0$

$x=+5$

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