Calculate the oxidation number of NaH2 PO4
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Na(alkali metal)=1
Hydrogen=1
Oxygen=(-2)
sum of all oxidation numbers of elements in a molecule is 0.
1×1+2×1+h×1+4×(-2)=1+2+h-8=0
h-5=0
h=5
(h is a variable. I assumed it to be oxidation number of Phosphorus.)
Hydrogen=1
Oxygen=(-2)
sum of all oxidation numbers of elements in a molecule is 0.
1×1+2×1+h×1+4×(-2)=1+2+h-8=0
h-5=0
h=5
(h is a variable. I assumed it to be oxidation number of Phosphorus.)
Musara:
Thank u very much
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