Calculate the oxidation number of oxygen in CH3COOH
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hey mate!!!
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siril:
its contradicting
Please stop yarr
my teacher explained very well.....but i coudn't tell it clearly
sorry ,maine carbon ka os nikal diya
ha
oxidation state of oxygen is -2
oxidation state of oxygen is -2
please rewrite the answer bro
sorry, abb mai edit nahi kar sakta
No problem thanks though!
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We have to consider another factor, that is electronegativity. The electronegative difference between C and H is [math]0.4[/math] according to the Pauling’s scale. This results in the shifting of the electron cloud density towards carbon resulting in the formation of 3 polar C-H bonds.
This will cause the 3 Hydrogen atoms to gain a [math]+1[/math] oxidation state which in turn causes the left Carbon to have a [math]-3[/math] oxidation state.
In the right, carbon is bonded to oxygen which is the second most electronegative element hence causing a shift in electron density towards the oxygen. This causes the top and right oxygens to gain a [math]-2[/math] and [math]-1[/math] charge since the former is bonded by a double bond and the latter is bonded by a single bond. This causes the right carbon to have [math]+3[/math] oxidation state.
and in last answer is -2
This will cause the 3 Hydrogen atoms to gain a [math]+1[/math] oxidation state which in turn causes the left Carbon to have a [math]-3[/math] oxidation state.
In the right, carbon is bonded to oxygen which is the second most electronegative element hence causing a shift in electron density towards the oxygen. This causes the top and right oxygens to gain a [math]-2[/math] and [math]-1[/math] charge since the former is bonded by a double bond and the latter is bonded by a single bond. This causes the right carbon to have [math]+3[/math] oxidation state.
and in last answer is -2
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