calculate the oxidation number of p in Mg3P4O7
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Explanation:
Mg3P4O7
Mg3 = +2 (since it is alkaline earth metal)
P4 = x
O7 = -2(from rule)
Mg3P4O7
3(+2) + 4(x) + 7(-2) = 0 (since it is neutral molecule)
6 + 4x - 14 = 0
4x - 8 = 0
4x = 8
x = 8÷4
x = +2
Therefore, the oxidation number of P is +2.
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ANSWER
Let X be the oxidation number of P in Mg
2
P
2
O
7
.
The Mg atoms have oxidation number of +2.
The O atoms have oxidation number of -2.
2(+2)+2X+7(−2)=0
2X−10=0
2X=10
X=+5
The oxidation number of P in Mg
2
P
2
O
7
is +5.
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