Question

Calculate the oxidation number of s in pbso4?

Answer 1

Answer:

The oxidation number of s in pbso4 is +2

Answer 2

Answer. Pb

Pb 2+

Pb 2+ [SO

Pb 2+ [SO 4

Pb 2+ [SO 4

Pb 2+ [SO 4 ]

Pb 2+ [SO 4 ] 2−

Pb 2+ [SO 4 ] 2−

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be x

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ]

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2−

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2∴x=+6

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2∴x=+6Therefore, the oxidation number of S in PbSO

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2∴x=+6Therefore, the oxidation number of S in PbSO 4

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2∴x=+6Therefore, the oxidation number of S in PbSO 4

Pb 2+ [SO 4 ] 2− Let the oxidation state of S be xThe oxidation state of O is -2Therefore, for [SO 4 ] 2− ⇒x+4(−2)=−2∴x−8=−2∴x=+6Therefore, the oxidation number of S in PbSO 4 is +6.