calculate the oxidation number of sulphur in H2SO5
InfinityToucher8:
As far as I know, there is no compound with the formula H2SO5
It is there.....
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Sulfur only has 6 valence electrons, so unless something very strange is going on, you can't get anything beyond S+6. The structure of this compound (if it even exists) probably does not have 5 oxygens directly on sulfur, it is most likely something that has a peroxy linkage such as:
HOO(HO)SO2 where 2 O's are double bonded to sulfur, one -OH group and one peroxy group -OOH.
This would give a sulfur in the S+6 oxidation state.
Sulfur only has 6 valence electrons, so unless something very strange is going on, you can't get anything beyond S+6. The structure of this compound (if it even exists) probably does not have 5 oxygens directly on sulfur, it is most likely something that has a peroxy linkage such as:
HOO(HO)SO2 where 2 O's are double bonded to sulfur, one -OH group and one peroxy group -OOH.
This would give a sulfur in the S+6 oxidation state.
oh... I'm sorry... I'm wrong
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