Question

calculate the oxidation number of the elements written in bold letters. [Cr(H²0)⁶]³+[fe(CN)⁶]³-,Hco-³pb³0⁴​

Answer 1

Answer:

Let x be the oxidation state of Fe in [Fe(CN)

6 ] 3−.

Since the overall charge on the complex is −3, the sum of oxidation states of all elements in it should be equal to −3.

Therefore, x+6(−1)=−3

or, x=+3