Calculate the oxidation number of the following underlined elements.
a) H-CHO b) H-COOH c)HClO3
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The oxidation number of carbon in methanaldehyde will be 0
The oxidation number of carbon in carboxylic acid will be +2
The oxidation number of chlorine in HClO3 will be -5
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1.the oxidation number of carbon in HCHO is 0. The compound methanol is also known as Formaldehyde. It is the simplest aldehyde.
2.Since H is in column 1 of the periodic table, it will share 1 electrons and use an oxidation state of 1 . Since O is in column 6 of the periodic table, it will share 6 electrons and use an oxidation state of 6 .
3.the oxidation state of Cl in HClO3 is +5.
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