Question

calculate the oxidation number of underlined atoms
a.H2S-O4​

Answer 1

Answer:

I hope help you

thank you

Answer 2

Answer:

6

Explanation:

oxidation number of H = +1

oxidation number of O = -2

let late oxidation number of Sulphur be 'x'

H2SO4

+1*2 + X + (-2)*4

by solving we get,

$2 + x - 8 = 0$

$- 6 + x = 0$

$x = 6$

I hope this helps you

please follow me and mark as brainliest