Question

Calculate the oxidation number of underlined atoms
a) HNO3 b)H,PO,​

Answer 1

What is Oxidation Number ?

$\huge{→}$ Oxidation number of an atom is the charge it appears to have when we count the electrons according to some arbitrary rules.

Here in Question :-

• Oxidation Number Of $\sf{HNO_3}$

Oxidation number of N = ?

We know that :

Oxidation Number of H = +1

Oxidation Number of O = -2

Let , Oxidation Number of N = x

So ,

$\large\implies{\sf 1+x(3×(-2))=0 }$

$\large\implies{\sf 1+x-6=0 }$

$\large\implies{\sf x=5 }$

• Oxidation Number of $\sf{HPO}$ :

Here

Oxidation Number of H = +1

Oxidation Number Of O = -2

Let , Oxidation Number of P = x

So ,

$\large\implies{\sf 1+x+(-2×1) }$

$\large\implies{\sf x=1 }$

________________________________________

Hence ,

Oxidation Number of N in $\sf{HNO_3}$ is +5

And

Oxidation Number of P in $\sf{HPO}$ is +1