calculate the oxidation number of underlined atoms KMMO4
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Explanation:
Let the Ox.no. of Mn in KMnO4
be x.
We know that, OX.no. of K=+1
Ox.no. of O=−2
So, Ox. no. K+ Ox. no. Mn + 4(Ox.no.O)=0
or +1+x+4(−2)=0
or +1+x−8=0
or x=+8−1=+7
Hence, Ox.no. of Mn in KMnO4 is +7.
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