calculate the oxidation number of underlined atoms of the following ¡)kmno4 ¡¡) k2cr207 ¡¡¡) na2s4o6
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Answered by
1
Answer:
Mn oxidation state in kmno4 is +7
cr oxd'n state in k2cr2o7 is +6
Explanation:
potassium oxd'n state is +1 oxygen oxd'n state is -2
I)x+1+4(-2)=0
x+1-8=0
x-7=0
x=7
2)2(1)+2x+7(-2)=0
2+2x-14=0
2x-12=0
x=6
Answered by
0
Answer:
+7
Explanation:
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