Calculate the Oxidation number of underlined element
a.NaBH4 b.Cr2O7
plzz don't spam
Answers
Answered by
3
Answer:
Cr−2O
7
−2
:2× (oxidation number of Cr ) +7(−2)=−2 ;
∴ ( Oxidation number of Cr) = 2+12=+6
Similar questions