Calculate the oxidation number of underlined element in the following: [a] KMnO4
[b] [Cr2 O7]-2
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Answered by
1
Answer
Cr−2O
7
−2
:2× (oxidation number of Cr ) +7(−2)=−2 ;
∴ ( Oxidation number of Cr) =
2
+12
=+6
Answered by
2
Answer:
1. KMnO4
1(+1) + x + 4(-2) = 0
x – 7 = 0
∴ x = + 7
Oxidation state of Mn = +7
2. Cr2O72-
2x + 7(-2) = -2
2x – 14 = – 2
2x = +12
∴ x = + 6
Oxidation state of Cr = +6.
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