Question

Calculate the oxidation number of underlined otoms

$\sqr}$
​

Answer 1

Answer:

+ 5

Explanation:

Given ;

Compound  NaH2PO4​

We have to find oxidation number of P .

Let x is oxidation number of P in NaH2PO4​

1 + 2 + x - 8 = 0

3 + x - 8 = 0

x - 5 = 0

x = + 5 .

Thus , oxidation number of P in NaH2PO4​ is + 5 .

Important things should you know ;

Alkali metal oxidation number is always considered + 1 .

For example ;  Na , K , Ru etc

Alkaline earth metals oxidation number is always considered + 2

For example ; Ca , Mg , Sr etc .

d block and p block elements show variation in their oxidation state or number .