calculate the oxidation of elements i.e average oxidation state and individual oxidation State a) tribromoctaoxide-Br, b) carbon suboxide- c, c) Tetrathionate ion.
Answers
Answered by
0
Answer:
(a) -16/3
TheBr3O8 compound has two types of oxidation states i.e. +6 and +4. Hence, the oxidation of bromine is -16/3.
(b) The structure of C3O2 is O=C=C=C=O. The carbon in the middle has 0oxidation state, whereas the carbons bonded to oxygen have a +2 oxidation state. On average, the oxidation state at carbon is [(2 + 2 + 0)/3] = +1.3. On the other hand, both oxygens have an oxidation state of -2.
Similar questions