Calculate the oxidation state of chromium (Cr) in CrO4
2-.
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I suppose the question should be what the oxidation state of Cr in chromate, CrO4^2-
Oxidation state of O is 2-, 4 O's makes 8-
(Oxidation state of Cr) + ( 8-) must equal 2-, hence oxidation state of Cr can only be 6+
Remember the sum of oxidation states in a ion always equals the electric charge of the ion
OR
I assume Cro4(2-) has been written in the way because cr can have +6 as its maximum oxidation state..
So let the oxidation state of cr be x and o Carries -2 charge
X+(-2*4)=-2
X-8=-2
X=+6
Cr has +6 oxidation state
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