Question

calculate the p.d. across each resistor in the circuit shown in the figure​

Answer 1

Answer:

Potential difference,V=5V

Explanation:

Potential difference,V=IR

As the resistors are in series add them

R =4+6+10=20 ohm

I=V/R=5/20=1/4=0.25A

V=IR=0.25x20=5V

pd across 4 ohm=0.25x4=1V

6 ohm=0.25x6=1.5V

10 ohm=0.25x10=2.5V

Answer 2

$\LARGE{ \underline{ \bf{Required \: answer:}}}$

What's given to us?

• A circuit with battery of emf 5 V.
• Three resistors joined end to end : 4 Ω, 6 Ω and 10 Ω.

We have to find:

• Potential difference across each resistor?

Step-by-step Explanation:

All the three resistors are joined end-to-end adjacent to each other, which means they are connected in series.

⇒ Req. = R1 + R2 + R3

⇒ Req. = 4 Ω + 6 Ω + 10 Ω

⇒ Req. = 20 Ω

Now in series combination, the current remains same throughout the circuit. So, finding current by using ohm's law:

⇒ V = IReq.

⇒ 5 V = I × 20 Ω

⇒ I = 1/4 A

Potential difference across each resistor:

1) Across 4 Ω

= IR1

= 1/4 A × 4 Ω

= 1 V

________________

2) Across 6 Ω

= IR2

= 1/4 A × 6 Ω

= 3/2 V

= 1.5 V

_________________

3) Across 10 Ω

= IR3

= 1/4 A × 10

= 5/2 V

= 2.5 V

Note!!

Don't get confused between the units. Volt (V) is the SI unit of voltage/potential difference, Amperes (A) is the SI unit of Current and Ohm's (Ω) is the SI unit of resistance.