Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)
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Given :
- Mass of the object = 5 kg.
- Acceleration due to gravity = 10 N/kg or 10 m/s².
- Height = h¹ = 3 m.
- Height = h² = 6 m.
To find :
Potential energy possessed by the body at two different heights.
Solution :
We know the formula for potential energy possessed by a body i.e,
⠀⠀⠀⠀⠀⠀⠀⠀⠀P·E = mgh
Where :
- P·E = Potential energy
- m = Mass of the body
- h = Height of the body
Potential energy of the body at height of 3 m :
By using the formula for Potential energy and substituting the values in it, we get :
==> P·E = mgh
==> P·E = 5 × 10 × 3
==> P·E = 150
∴ P·E = 150 J.
Hence the potential energy possessed by the body is 150 J.
Potential energy of the body at height of 6 m :
By using the formula for Potential energy and substituting the values in it, we get :
==> P·E = mgh
==> P·E = 5 × 10 × 6
==> P·E = 300
∴ P·E = 300 J.
Hence the potential energy possessed by the body is 300 J.
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