Question

calculate the partial pressure of 14 gram of nitrogen of volume 1 litre​

Answer 1

Answer:

Explanation:

PV = nRT V = 10 litre T = 27ºC = 300K

nHe = 0.4/4 = 0.1

 N2 = 1.4/ 28= 0.05, 

O2 = 1.6/32= 0.05

Total no. of moles = 0.1 + 0.05 + 0.05  0.2

PV = nRT  P× 10 = 0.2 × 0.082 × 300 = 0.04926  P = 0.492 atm

Partial pressure = Total pressure × molefraction

PHe = 0.492 × 0.1/ 0.2

 = 0.246 atm

PN2 = 0.492 × 0.05/ 0.2

 = 0.123 atm

PO2 = 0.492 × 0.05/0.2

 = 0.123 atm

Answer 2

Answer:

Explanation:

It is the same as the one I have is a will call you in a few minutes and I'll be there in about the same as 55 litres

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