Question

calculate the percent composition of elements methanol​

Answer 1

values put kar dena

Explanation:

The equation for percent composition is (mass of element/molecular mass) x 100.

Answer 2

AnSwer :-

Molecular formula of methanol is ⠀⠀⠀⠀ CH$_3$OH

Molecular mass of methanol

= 1 × 12.01 + 4 × 1.008 + 1 × 16.0

= 32.042 gm.

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$\sf percent \: composition \: of \: carbon$

$\sf = \frac{mass \: of \: carbon \times 100}{molecular \: mass \: of \: CH _{3}OH }$

$\sf = \frac{12.01}{32.04} \times 100 = 37.48\%$

Thus, the percent composition of carbon is 37.48% .

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$\sf percent \: composition \: of \: hydrogen$

$\sf = \frac{mass \:of \: hydrogen }{molecular \: mass \: of \: CH_{3}OH}$

$\sf = \frac{4.032}{32.042} \times 100 = 12.5\%$

Thus, the percent composition of Hydrogen is 12.5%.

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$\sf percent \: composition \: of \: oxygen$

$\sf = \frac{16 \times 100}{32.4} = 49.93\%$

thus, the percent composition of oxygen is 49.93% .