Calculate the percent composition of water in zinc sulfate heptahydrate (ZnSO4* 7H2O)
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Given :
ZnSO₄.7H₂O
To find :
Percentage Composition of water in ZnSO₄.7H₂O.
Solution :
Zn = 65
S = 32
O = 16
H = 1
ZnSO₄ = 65 + 32 + 4×16
= 65 + 32 + 64
= 161
H₂O = 2×1 + 16
= 2 + 16
= 18
Formula Mass of ZnSO₄.7H₂O = 161 + (7×18)
= 161 + 126
= 287
Percentage of water = (126 / 287)×100
= 43.9%
Percentage composition of water in ZnSO₄.7H₂O = 43.9%
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