Question

Calculate the percent ionic character of H—F bond. Given that the electronegativity difference for HF is 1.9.​

Answer 1

Answer:

Explanation:

To calculate % gornic character we consider 100 % iconic bond.

μ=Q×d

=(1.60×10

−19

C)×0.83×10

−10

m×(

3.336×10

−30

1D

)

% gonic character =

3.980

1.82

×100

=45.70%

% covalent character = (100-% ginoc character)

=54.3%