Question

calculate the percent of available chlorine in sample of 3.5 gram of bleaching powder which was dissolved in hundred ml of water 25 ml of this solution on treatment with K and dilute acid required 20 ml of 0.125 normal sodium thiosulphate solution​

Answer 1

Answer:

Explanation:

equivalent = 2.5

for 25 ml - 2.5

100 ml - 10

equivalent of caocl2 = 10

moles*f*1000=10

moles*2*1000=10

0.005=moles

w/71=0.005

w=0.355

equivalent of cl2 = 0.355

percentage availability = 0.355/3.5 * 100

=10