Question

calculate the percent of water of hydration in oxalic acid crystals

Answer 1

Answer:

Molecular weight of oxalic acid (H

2

C

2

O

4

.2H

2

O) is 126 g/mol.

Molarity of 0.2 N oxalic acid (H

2

C

2

O

4

.2H

2

O) solution =

2

0.2

=0.1 M

Amount of solution =50 mL =0.05 L

So, amount of oxalic acid =126×0.1×0.05=0.63 g

Hence, the correct option is C

Answer 2

Explanation:

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