Question

Calculate the percentage by mass of sulphur in tetraoxosulphate 6 acid

Answer 1

Molecular mass of H2SO4=2+32+(16×4)=98g

Molar mass of S in 1 mole of H2SO4=32g

Therefore % of S in H2SO4=9832×100=32.65%.

Answer 2

Answer:

Explanation:

To find the percentage composition of an element in a compound you have to find the relative molecular mass of the compound and the element you want to find.

H2SO4= 1*2+(32+16*4) = 98

S= 32

Then you divide the element by the compound and multiply by 100

$\frac{S}{H2SO4}$  = 32/98(100)

= 32.6%