Calculate the percentage by mass of trilead tetraoxide
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Answer:
Explanation:
Trilead tetraoxide is PB3O4
Pb = 207.2, O = 16
Mass of 1 mole of compound is
3(207.2) +4(16)
621.6 + 64 = 685.6g
% Pb in the molecule = 612.6/685.6 = 90.6%
%O in the molecule = 64 / 685.6 = 9.4%
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