Question

calculate the percentage change in acceleration due to gravity at the 1600 km height from the surface of the earth

Answer 1

Hey mate...

(Radius of earth=6.3km
=6300m
Gravitational constant,G=6.67×10^-11
Mass of earth = 10×10^24kg


The forcula for gravity is

g=GM/R2..
At surface g becomes

$\frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} }{ {6300}^{2} }$
=9.8

For height of 1600km

g=GM/(R+1600)^2

=

$\frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} }{ {(6300 + 1600)}^{2} }$
g =

Answer 2

Answer : -36%

Step By Step Explanation is given in the enclosed file.