Question

calculate the percentage compasition of the
elements present in magnesium carbonate
How many kilogram of Co₂ can be obtained
by heating 1kg of 9% pure magnesium
carbonate​

Answer 1

Answer:

ANSWER

MgCO

3

→MgO+CO

2

The molar masses of MgCO

3

and MgO are 24+12+48=84 g/mol and 24+16=40 g/mol respectively.

Thus, 8 g MgO will be obtained from

40

84

×8=16.8 mg of MgCO

3

.

The percentage purity of magnesium carbonate in the sample is

20

16.8

×100=80%

Explanation:

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