Question

Calculate the percentage composition by mass of oxygen in a compound Ca(NO3)2.​

Answer 1

Answer:

The molar mass of Ca(NO 3 ) 2

=40.1+2×(14+3(16))=40.1+2×(62)=164.1g/mol.

1 mole (164.1 g) of calcium nitrate will contain 6 moles of O atoms.

The atomic mass of oxygen is 16 g/mol.

6 moles of oxygen atoms corresponds to 6×16=96g.

The percent of oxygen in calcium nitrate =

164.1

96×100

=58 %

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