calculate the percentage composition of butyric acidd
Answers
Explanation ⇒
Chemical formula of Butryic acid = C₄H₈O₂.
It contains three different atoms, namely Carbon Hydrogen and Oxygen.
Molar mass of Butryic acid or C₄H₈O₂ = 12 × 4 + 1 × 8 + 16 × 2
= 48 + 8 + 32
= 48 + 40
= 88 g/mole.
Now, mass of carbon in Butryic acid or C₄H₈O₂ = 12 × 4
= 48 g.
∴ % composition of Carbon in Butryic acid = (mass of carbon in compound/molar mass of compound) × 100
= 48/88 × 100
= 54.54 %
mass of hydrogen in Butryic acid or C₄H₈O₂ = 1 × 8
= 8 g.
∴ % composition of Hydrogen in Butryic acid = (mass of Hydrogen in compound/molar mass of compound) × 100
= 8/88 × 100
= 100/11
= 9.09 %
mass of Oxygen in Butryic acid or C₄H₈O₂ = 16 × 2
= 32 g.
∴ % composition of Oxygen in Butryic acid = (mass of Oxygen in compound/molar mass of compound) × 100
= 32/88 × 100
= 36.36 %
Hope it helps.