Question

Calculate the percentage composition of each element in potassium chlorate(KCLO3)

Answer 1

$\bold{MOLECULAR \: WEIGHT \: OF \: POTASSIUM A: CHLORATE(KClO_3)}$

K = 39

Cl = 35.5

O = 16

Molecular mass = K + Cl + 3(O)

= 39 + 35.5 + 3(16)

= 39 + 35.5 + 48

=122.5 g

◼For Potassium (K)

Weight of pottasium present in potassium chlorate = 39 g

$\boxed{Percentage \: composition = \dfrac{Weight \: of \: element \: in \:the\: compound }{Gram molecular weight of compound }}$

${Percentage \: composition = \dfrac{39}{122.5} \times 100}$

${Percentage \: composition \: of \: K=31.8 \%}$

◼For Chlorine (Cl)

Weight of Chlorine present in potassium chlorate = 35.5 g

$\boxed{Percentage \: composition = \dfrac{Weight \: of \: element \: in \:the\: compound }{Gram molecular weight of compound }}$

${Percentage \: composition = \dfrac{35.5}{122.5} \times 100}$

${Percentage \: composition \: of \: Cl=28.9 \%}$

◼For oxygen (O)

Weight of oxygen present in potassium chlorate = 48 g

$\boxed{Percentage \: composition = \dfrac{Weight \: of \: element \: in \:the\: compound }{Gram molecular weight of compound }}$

${Percentage \: composition = \dfrac{48}{122.5} \times 100}$

${Percentage \: composition \: of \: O=39.1 \%}$

Answer 2

Answer:

% of potassium =31.8%

%of chlorine =28.9%

% of oxygen =39.1%

Explanation:

The molar mass of potassium is 39 g.. multiply this by 100 .And devide by the molar mass of the compound. similarly do it with chlorine. And oxygen is three times so multiply the molar mass of oxygen (16) with 3 then multiply with 100 and devide by the total mass of the compound.