calculate the percentage composition of each element in the molecule qcetic acid (CH3COOH)
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Molecular mass of CH3COOH is 60g
now., first let us see the% composition of C,
•mass of c in compound=2×12=24g
mass of compound=60g
% composition(C) = 24*100/60
(C) =40%
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•mass of O in compound= 2×16=32g
mass of compound=60g
% composition(O)= 32*100/60
(O) =53.33%
,...................................................................................
•mass of H in compound=4×1=4g
mass of compound=60g
% composition(H)= 4*100/60
(H) =6.66%
now., first let us see the% composition of C,
•mass of c in compound=2×12=24g
mass of compound=60g
% composition(C) = 24*100/60
(C) =40%
--------------------------------------------------------------------
•mass of O in compound= 2×16=32g
mass of compound=60g
% composition(O)= 32*100/60
(O) =53.33%
,...................................................................................
•mass of H in compound=4×1=4g
mass of compound=60g
% composition(H)= 4*100/60
(H) =6.66%
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