Question

Calculate the percentage composition of K, Cr,O atom in K2CrO7 molecules where K=36,Cr=52,O=16

Answer 1

Answer:k -20%,cr-10%,o-70%

Explanation:

Answer 2

Answer:

K= 36÷104×100

= 34.615 %

Cr= 52÷104×100

= 50 %

O= 16÷104×100

= 15.384%

Total= 99.999%