Calculate the percentage composition of K, Cr,O atom in K2CrO7 molecules where K=36,Cr=52,O=16
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Answered by
1
Answer:k -20%,cr-10%,o-70%
Explanation:
Answered by
3
Answer:
K= 36÷104×100
= 34.615 %
Cr= 52÷104×100
= 50 %
O= 16÷104×100
= 15.384%
Total= 99.999%
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