calculate the percentage composition
of Mn in KMnO4
Answers
Answered by
24
Answer:
Percentage Composition
KMnO4
=(39+55+16×4)
=(94 +64)
=158%
- K
=39/158
=0.247
=24.7%.
- Mn
=55/158
=0.348
=34.8%.
- O
=64/158
=0.405
=40.5%.
Answered by
8
Explanation:
molecular mass of potassium permanent
molecular formula of potassium permanent is kmno4
%of potassium in potassium permanent is
=39÷158×100 =24.68
%of manganese in potassium permanent is
=55÷158×100 =34.81
%of oxygen in potassium permanent is
= 64÷158×100 =40.50
add 3 also
24.68
34.81
40.50
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