calculate the percentage composition of nitrogen in urea. urea formula is NH2CONH4. N=14
H=1
C=12
O=16
show that the molecular formula of urea is CH4ON2 if the %by mass of 02 atoms is one mole of urea molecule is 26.66%
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Answer:
Molecular weight of H
2
NCONH
2
=4+28+12+16=60g
60g of urea contains 28g of N
∴ % of N=
60
28
×100=46.6%
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