Question

Calculate the percentage composition of "S" in H2so4 ??
Answer with full solution


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Answer 1

Molecular mass of H2SO4 = 2+32+(16×4)=98g

Molar mass of S in 1 mole of H2SO4 = 32g

Therefore % of S in H2SO4 = 32 / 98 × 100 = 32.65%

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Answer 2

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⟹ Asked :-

Calculate the percentage composition of "S" in H2so4 ??

⟹ As we know :-

⟹ $\frac{mass \: of \: sulfhur}{molecular \: mass \: of \: compound} \times 100$

⟹ Solution :-

⟹ $\frac{mass \: of \: sulfhur}{molecular \: mass \: of \: compound} \times 100$

⟹ $\frac{32 \times 1}{1 \times 2 + 32 + 16 \times 4} \times 100$

⟹ $\frac{32}{98} \times 100$

⟹ $32.65$

Required answer is 32.65

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