Chemistry, asked by asmitaghosh249, 1 month ago

Calculate the percentage composition of Sodium carbonate, Na2CO3.

[Na = 23, C = 12, O = 16]

Answers

Answered by satyamjoshi74
1

Explanation:

Percentage of Sodium [Na] in Sodium Carbonate [Na2CO3] = 46/106 x 100 = 43.40%. Percentage of Carbon [C] in Sodium Carbonate [Na2CO3] = 12/106 x 100 = 11.32%.

Answered by sekhrauza
1

Explanation:

Percentage of Sodium [Na] in Sodium Carbonate [Na2CO3] = 46/106 x 100 = 43.40%. Percentage of Carbon [C] in Sodium Carbonate [Na2CO3] = 12/106 x 100 = 11.32%.

Similar questions