Chemistry, asked by asmitaghosh249, 3 months ago

Calculate the percentage composition of Sodium carbonate, Na2CO3.

[Na = 23, C = 12, O = 16]

Answers

Answered by satyamjoshi74
1

Explanation:

Percentage of Sodium [Na] in Sodium Carbonate [Na2CO3] = 46/106 x 100 = 43.40%. Percentage of Carbon [C] in Sodium Carbonate [Na2CO3] = 12/106 x 100 = 11.32%.

Answered by sekhrauza
1

Explanation:

Percentage of Sodium [Na] in Sodium Carbonate [Na2CO3] = 46/106 x 100 = 43.40%. Percentage of Carbon [C] in Sodium Carbonate [Na2CO3] = 12/106 x 100 = 11.32%.

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