Question

- Calculate the percentage composition of the elements present in magnesium carbonate. How many kilogram
of CO2. can be obtained by heating lkg of 90% pure magnesium carbonate.​

Answer 1

Answer:

Explanation:

Reaction-

MgCO3>>>>MgO+CO2  

Given 1 kg  MgCO3  which is 90% pure.

Thus real mass of  MgCO3  is 90% of 1kg

=900g

Molecular masses

MgCO3=24×1+12×1+16×3=84  

MgO=24×1+16×1=40  

CO2=12×1+16×2=44  

Thus 84 units (grams) of  MgCO3  gives 44 units (grams) of  CO2  

Thus 900 units of  MgCO3  will give

(90084×44)  units of  CO2  

=approximately  471.43  units of  CO2  

Thus,

1kg, 90% pure  MgCO3  will give approximately 471.43 grams of  CO2  

HAPPY TO HELP

Answer 2

Explanation:

percentage of carbon

=14.29%