Question

Calculate the percentage composition of the elements present in calcium carbonate .How many kilogram of CO2 can be obtained by heating 2kg of 85% pure calciumcarbonate .
The balanced chemical equation is
CaCO3+ heat------>CaO + CO2 .Molar mass of CaCO3 is 100 g mol-1​

Answer 1

Explanation:

Chemical reaction involved is:

CaCO3→CaO+CO2

Molar mass of CaCO3=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO3 produces 1 mol of CO2 i.e. 22.4 L at STP.

∴50 g CaCO3 will produce 10022.4×50=11.2 L CO2 at STP.

was this helpful,???