Question

Calculate the percentage composition of the elements present in calcium carbonate .How many kilogram of CO2 can be obtained by heating 2kg of 85% pure calciumcarbonate .
The balanced chemical equation is
CaCO3+ heat------>CaO + CO2 .Molar mass of CaCO3 is 100 g mol-1​

Answer 1

Answer:

ANSWER

Chemical reaction involved is:

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO

3

produces 1 mol of CO

2

i.e. 22.4 L at STP.

∴50 g CaCO

3

will produce

100

22.4

×50=11.2 L CO

2

at STP.