Calculate the percentage composition of the elements present in calcium carbonate .How many kilogram of CO2 can be obtained by heating 2kg of 85% pure calciumcarbonate .
The balanced chemical equation is
CaCO3+ heat------>CaO + CO2 .Molar mass of CaCO3 is 100 g mol-1
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Answer:
hii answer is
Explanation:
Chemical reaction involved is:
CaCO
3
→CaO+CO
2
Molar mass of CaCO
3
=40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO
3
produces 1 mol of CO
2
i.e. 22.4 L at STP.
∴50 g CaCO
3
will produce
100
22.4
×50=11.2 L CO
2
at STP.
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